Swift Testing for Unit Tests PART 1 (#5119)

* migrated a lot of unit tests to Swift Testing and added a new implementation for deferred fulfillment

more tests migration

Cleaned the code manually to establish some good patterns

more code improvements

some more code improvements

removed empty tests

update project

* more pr suggestions and cleanups

* removed the TestSetup pattern

* fixing claude not reusing tests

* pr suggestion + added indent rule to swiftformat so that we can prevent AIs to change that
This commit is contained in:
Mauro
2026-02-19 16:20:47 +01:00
committed by GitHub
parent fc03e05697
commit 7982aef855
118 changed files with 4630 additions and 4129 deletions
+15 -13
View File
@@ -8,28 +8,30 @@
@testable import ElementX
import Foundation
import XCTest
import Testing
class ArrayTests: XCTestCase {
func testGrouping() {
XCTAssertEqual([].groupBy { $0 == 0 }, [])
@Suite
struct ArrayTests {
@Test
func grouping() {
#expect([].groupBy { $0 == 0 } == [])
XCTAssertEqual([0].groupBy { $0 == 0 }, [[0]])
#expect([0].groupBy { $0 == 0 } == [[0]])
XCTAssertEqual([1].groupBy { $0 == 0 }, [[1]])
#expect([1].groupBy { $0 == 0 } == [[1]])
XCTAssertEqual([0, 0, 0].groupBy { $0 == 0 }, [[0, 0, 0]])
#expect([0, 0, 0].groupBy { $0 == 0 } == [[0, 0, 0]])
XCTAssertEqual([1, 1, 1].groupBy { $0 == 0 }, [[1], [1], [1]])
#expect([1, 1, 1].groupBy { $0 == 0 } == [[1], [1], [1]])
XCTAssertEqual([1, 0, 0, 1].groupBy { $0 == 0 }, [[1], [0, 0], [1]])
#expect([1, 0, 0, 1].groupBy { $0 == 0 } == [[1], [0, 0], [1]])
XCTAssertEqual([0, 0, 1, 0].groupBy { $0 == 0 }, [[0, 0], [1], [0]])
#expect([0, 0, 1, 0].groupBy { $0 == 0 } == [[0, 0], [1], [0]])
XCTAssertEqual([0, 0, 0, 1, 2, 3, 0].groupBy { $0 == 0 }, [[0, 0, 0], [1], [2], [3], [0]])
#expect([0, 0, 0, 1, 2, 3, 0].groupBy { $0 == 0 } == [[0, 0, 0], [1], [2], [3], [0]])
XCTAssertEqual([0, 0, 0, 1, 2, 3, 0, 0].groupBy { $0 == 0 }, [[0, 0, 0], [1], [2], [3], [0, 0]])
#expect([0, 0, 0, 1, 2, 3, 0, 0].groupBy { $0 == 0 } == [[0, 0, 0], [1], [2], [3], [0, 0]])
XCTAssertEqual([0, 0, 0, 1, 0, 2, 3, 0, 0].groupBy { $0 == 0 }, [[0, 0, 0], [1], [0], [2], [3], [0, 0]])
#expect([0, 0, 0, 1, 0, 2, 3, 0, 0].groupBy { $0 == 0 } == [[0, 0, 0], [1], [0], [2], [3], [0, 0]])
}
}